Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 11 - Fluids - Check Your Understanding - Page 287: 5

Answer

$\text{noticeable amount of water is left in it}$

Work Step by Step

$P_2$ = $P_1$ + $\rho$gh $\text{But tank is closed,}$ $\therefore$ $\text{$P_1$ = 0}$ $P_2$ = $\text{0}$ + $\rho$gh $P_2$ = $\rho$gh $\text{$P_2$ = 1000$\times$9.8$\times$15}$ $P_2$ = 147000 Pa $\text{After a valve is then opened at the bottom of the tank}$ $P_1$ = 101000 Pa $P_2$ - $P_1$ = $\rho$gh ($P_2$ - $P_1$)/$\rho$g= h h= (147000-101000)/(1000$\times$9.8) h=4.69 m $\text{So, noticeable amount of water is left in it}$
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