Answer
The magnitude of the impulse is the same in all three cases.
Work Step by Step
To calculate the impulse $J$, we can find the area under the force versus time graph.
(a) $J = (2F_0)(6~t_0) = 12~F_0~t_0$
(b) $J = (4F_0)(3~t_0) = 12~F_0~t_0$
(c) $J = \frac{1}{2}(2F_0)(12~t_0) = 12~F_0~t_0$
The magnitude of the impulse is the same in all three cases.
