Answer
The magnitude of the average force on the passenger during the collision is $~~3.52\times 10^5~N$
Work Step by Step
In part (c), we found that the magnitude of the impulse is $~~1760~kg~m/s$
We can find the magnitude of the average force on the passenger during the collision:
$F~t = J$
$F = \frac{J}{t}$
$F = \frac{1760~kg~m/s}{5.0\times 10^{-3}~s}$
$F = 3.52\times 10^5~N$
The magnitude of the average force on the passenger during the collision is $~~3.52\times 10^5~N$.
