Answer
The magnitude of the average force on the wall during each impact is $~~100~N$
Work Step by Step
In part (a), we found that the magnitude of the impulse during each impact is $1.0~kg~m/s$
We can find the magnitude of the average force on the wall during each impact:
$F~t = J$
$F = \frac{J}{t}$
$F = \frac{1.0~kg~m/s}{10\times 10^{-3}~s}$
$F = 100~N$
The magnitude of the average force on the wall during each impact is $~~100~N$
