Answer
1.5 kJ
Work Step by Step
According to the work-energy theorem,
$K_{f}-K_{i}=W$
$K_{i}=\frac{1}{2}mv_{i}^{2}=\frac{1}{2}m\times0^{2}=0$
Therefore, we can write
$K_{f}-0=W$
$= Fd\cos\theta=200\,N\times8.0\,m\times\cos 20^{\circ}$
$=1500\,J$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 7 - Kinetic Energy and Work - Problems - Page 175: 68
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