Answer
-155 J
Work Step by Step
The gravitational force $F=mg=25.0\,kg\times9.8\,m/s^{2}=245\,N$
Displacement $d=1.50\,m$
Now, the gravitational force acts vertically downwards and the displacement is upwards and parallel to the incline angled at $25^{\circ}$ with the horizontal. Therefore, the angle between $\vec{F}$ and $\vec{d}$ is $(90+25)^{\circ}=115^{\circ}$
$W=Fd\cos\theta=245\,N\times1.50\,m\times\cos150^{\circ}=-155\,J$
