Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 42 - Nuclear Physics - Problems - Page 1305: 52c

Answer

$U_1= 86 MeV $

Work Step by Step

$U_1 \approx U_2 (\frac{q_{Pb} q_C }{q_{Rn} q_{He}}) $ Where $U_2 = 30 MeV$ $q_{Pb} = 82 e$ $q_C = 6.0e$ $q_{Rn} = 86 e$ $q_{He} = 2.0 e$ so $U_1 = 30 MeV (\frac{(82 e) (6.0e) }{(86 e)(2.0 e)}) $ $U_1= 86 MeV $
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