Answer
$$-1.30 \mathrm{\ MeV} $$
Work Step by Step
$\begin{aligned} Q_{4} =&\left({m_{235_U}} - {m_{230_{Th}}} -{m_{5_{He}}
}\right) c^{2} \\ \\ = &(235.0439 \mathrm{u}-230.0331 \mathrm{u}-5.0122 \mathrm{u})(931.5 \mathrm{MeV} / \mathrm{u}) \\ \\ =&-1.30 \mathrm{\ MeV} \end{aligned}$
