Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 40 - All About Atoms - Problems - Page 1251: 77

Answer

$6.63\times10^{-34}\;J.s$

Work Step by Step

$E=\frac{ch}{\lambda_{min}}$ or, $h=\frac{E\lambda_{min}}{c}$ Substituting the given values, we obtain the Planck constant: $h=\frac{40\times 10^{3}\times1.6\times10^{-19}\times 31.1\times10^{-12}}{3\times10^{8}}\;J.s=6.63\times10^{-34}\;J.s$
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