Answer
$a = 7.2\times 10^4~m/s$
Work Step by Step
We can find the acceleration of a silver atom:
$a = \frac{\mu_B~\frac{dB}{dt}}{M}$
$a = \frac{(9.27\times 10^{-24}~J/T)(1400~T/m)}{1.8\times 10^{-25}~kg}$
$a = 7.2\times 10^4~m/s$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 40 - All About Atoms - Problems - Page 1247: 13
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