Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 4 - Motion in Two and Three Dimensions - Problems - Page 93: 135b

Answer

$y = -37.7~m$

Work Step by Step

We can find the vertical displacement $y$ at $t = 2.30~s$: $y = v_{0y}~t+\frac{1}{2}a_y~t^2$ $y = -(15.0~m/s)~(sin~20.0^{\circ})(5.00~s)+\frac{1}{2}(-9.8~m/s^2)~(2.30~s)^2$ $y = -37.7~m$
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