Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 4 - Motion in Two and Three Dimensions - Problems - Page 93: 135a

Answer

32.4 m

Work Step by Step

Given: $v_{0}=15.0\,m/s$, $\theta_{0}=-20.0^{\circ}$ and $t=2.30\,s$ Equation used: Horizontal displacement $x=(v_{0}\cos\theta_{0})t$ Result: $x= (15\,m/s\times\cos(-20^{\circ}))2.30\,s=32.4\,m$
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