Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 38 - Photons and Matter Waves - Questions - Page 1181: 10d

Answer

The de Broglie wavelength remains the same.

Work Step by Step

We can use Equation (38-20) to find an expression for the de Broglie wavelength: $\frac{1}{2}mv^2 = \frac{h^2}{2m \lambda^2}$ $\lambda^2 = \frac{h^2}{m^2~v^2}$ $\lambda = \frac{h}{m~v}$ Since the electron is moving perpendicular to the magnetic field, there is a magnetic force on the electron that causes the electron to move in a circle. However, the speed does not change. Therefore, the de Broglie wavelength remains the same.
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