Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 38 - Photons and Matter Waves - Questions - Page 1181: 10c

Answer

The de Broglie wavelength remains the same.

Work Step by Step

We can use Equation (38-20) to find an expression for the de Broglie wavelength: $\frac{1}{2}mv^2 = \frac{h^2}{2m \lambda^2}$ $\lambda^2 = \frac{h^2}{m^2~v^2}$ $\lambda = \frac{h}{m~v}$ Since the electron is moving in the same direction as the magnetic field, the magnetic force on the electron is zero. The speed does not change. Therefore, the de Broglie wavelength remains the same.
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