Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 37 - Relativity - Problems - Page 1146: 17a

Answer

The spatial coordinate of the event according to S' is $~~x' = 138~km$

Work Step by Step

We can find $\gamma$: $\gamma = \frac{1}{1-\beta^2}$ $\gamma = \frac{1}{1-0.950^2}$ $\gamma = 3.20$ We can find the spatial coordinate $x'$: $x' = \gamma~(x-vt)$ $x' = 3.20~[100~km-(0.950)(3.0\times 10^8~m/s)(200\times 10^{-6}~s)]$ $x' = (3.20)(43~km)$ $x' = 138~km$ The spatial coordinate of the event according to S' is $~~x' = 138~km$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.