Answer
$L = 30~ly$
Work Step by Step
In part (a), we found that $\gamma = \frac{2300}{3}$
We can find the contracted length $L$:
$L = \frac{L_0}{\gamma}$
$L = \frac{23,000~ly}{2300/3}$
$L = 30~ly$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 37 - Relativity - Problems - Page 1146: 15b
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