Answer
$\theta_R=1.3*10^{-4}rad$
Work Step by Step
We have all the information need to determine the angular separation, $\theta_R$, at which the eye will resolve them by using Rayleigh’s criterion (equation 36-16.)
$\theta_R=1.22\lambda/d$
Where $\lambda$ is the wavelength and $d$ is the diameter of the aperture
$\theta_R=1.22\lambda/d$
$\theta_R=1.22(550*10^{-9}m)/(5.0*10^{-3}m)$
$\theta_R=1.3*10^{-4}rad$
