Answer
$D=1.1*10^4km$
Work Step by Step
We are given all of the information needed to find the farthest possible separation of two objects on Mars , L, from an observer on earth (using his naked eyes) using equation (36-17).
$L=\frac{Dd}{1.22 \lambda}$ (36-17)
where D is the separation of the objects, d is the diameter of the pupils, and lambda is the wavelength.
Solving for D, we obtain:
$D=\frac{1.22*8.0*10^{10}m*550*10^{-9}m}{5.0*10^{-3}m}$
$D=1.1*10^7m$
$D=1.1*10^4km$
