Answer
$\lambda=588nm$
Work Step by Step
We know that
$d=m(\frac{\lambda}{2})$
This can be rearranged as:
$\lambda=\frac{2d}{m}$
We plug in the known values to obtain:
$\lambda=\frac{2(0.233\times 10^{-3})}{792}=588nm$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 35 - Interference - Problems - Page 1078: 79
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