Answer
$\theta_2 = 38^{\circ}$
Work Step by Step
In part (a), we found that $n_1 = 1.7$
According to Snell's law:
$n_1~sin~\theta_1 = n_2~sin~\theta_2$
We can find $\theta_2$:
$n_1~sin~\theta_1 = n_2~sin~\theta_2$
$sin~\theta_2 = \frac{n_1~sin~\theta_1}{n_2}$
$\theta_2 = sin^{-1}~(\frac{n_1~sin~\theta_1}{n_2})$
$\theta_2 = sin^{-1}~(\frac{1.7~sin~60^{\circ}}{2.4})$
$\theta_2 = sin^{-1}~(0.613435)$
$\theta_2 = 38^{\circ}$
