Answer
The average acceleration between $~~t = 0~~$ and $~~t = 2.0~s~~$ is $~~-0.785~cm/s^2$
Work Step by Step
In part (b), we found the following:
When $t = 0$, then $v = 1.57~cm/s$
When $t = 2.0~s$, then $v = 0$
We can find the average acceleration between $t = 0$ and $t = 2.0~s$:
$a_{ave} = \frac{\Delta v}{\Delta t}$
$a_{ave} = \frac{0-1.57~cm/s}{2.0~s-0}$
$a_{ave} = -0.785~cm/s^2$
The average acceleration between $~~t = 0~~$ and $~~t = 2.0~s~~$ is $~~-0.785~cm/s^2$
