Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems - Page 38: 97b

Answer

$t = 4.95~s$

Work Step by Step

We can find the time it takes to fall $120~m$: $y = \frac{1}{2}at^2$ $t = \sqrt{\frac{2y}{a}}$ $t = \sqrt{\frac{(2)(120~m)}{9.80~m/s^2}}$ $t = 4.95~s$
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