Answer
$v_{0}=3.70m/s$
Work Step by Step
Recall the equation:
$x=v_{0}t+\frac{1}{2}at^{2}$
We simplify the equation and obtain:
$v_{0}=\frac{x}{t}-\frac{1}{2}at=\frac{.544m}{.200s}-\frac{1}{2}(-9.8m/s^{2})(.200s)=3.70m/s$
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