Answer
The rate at which water flows out of the container is $158kg/s$
Work Step by Step
First we must find the mass which we can solve using $ρ=\frac{m}{V}$
$m=ρV=(5700m^{3})(10^{3}kg/m^{3})=5.7\times10^{6}kg$
We then convert time to seconds
$t=(10h)(\frac{3600s}{1h})=3.6\times10^{4}s$
To find the rate of flow rate we must divide mass by time:
$flowrate=\frac{m}{t}=\frac{5.7\times10^{6}kg}{3.6\times10^{4}s}=158kg/s$
