Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 1 - Measurement - Problems - Page 10: 22a

Answer

$19.32 g/ 1 cm^3=19.32 g/cm^3$ $27.63 g/19.32 g/cm^3=1.430 cm^3$ $1.430 cm^3/100^3=1.430*10^{-6} m^3$ $1.430*10^{-6} m^3\div(1*10^{-6})m=1.430 m^2$

Work Step by Step

The density of gold = mass of gold/volume of gold Convert the unit into meter$^3$ by using (1m=100cm)$^3$ z=1*10$^{-6}$ m according to the metric prefixes. $volume=base area*thickness$ $area=volume/thickness$
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