Answer
$5.49 \ km/h$
Work Step by Step
We use conservation of energy to find:
$\frac{1}{2}mv^2 = \frac{1}{2}kx^2 $
$v=\sqrt{\frac{kx^2}{m}}=\sqrt{\frac{(1.3\times10^6N)(.05m)^2}{1400}}=1.52 \ m/s = 5.49 \ km/h$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 7 - Exercises and Problems - Page 126: 44
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
