Answer
Please see the work below.
Work Step by Step
We know that according to law of conservation of energy
$(\frac{1}{2})mv^2=mg(L-Lcos(50))$
This simplifies to:
$v=\sqrt{2g(L-Lcos(50))}$
We plug in the known values to obtain:
$v=\sqrt{(2)(9.8)(3.2-3.2cos(50))}$
$v=4.7\frac{m}{s}$
