Answer
Please see the work below.
Work Step by Step
We know that
$\Delta K=-f_k d$
This can be rearranged as:
$d=\frac{\Delta K}{-f_k}$
We plug in the known values to obtain:
$d=\frac{\frac{-1}{2}mv^2}{-\mu_k mg}$
$d=\frac{v^2}{2\mu g}$
$d=\frac{8.2}{2\times 0.023\times 9.8}=22.71m$
