Answer
Please see the work below.
Work Step by Step
We know that according to law of conservation of energy
$mgh=(\frac{1}{2})Kx^2$
This simplifies to:
$h=\frac{Kx^2}{2mg}$
$h=\frac{(430)(0.71)^2}{(2)(0.120)(9.8)}=92m$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 7 - Exercises and Problems - Page 125: 21
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