Answer
Please see the work below.
Work Step by Step
We know that
$cos(\theta)=\frac{A.B}{|A||B|}$
$cos(\theta)=\frac{(\frac{1}{3})|A|^2}{|A||A|}=\frac{1}{3}$
Now we can find the angle as
$\theta=cos^{-1}(\frac{1}{3})=71^{\circ}$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 6 - Exercises and Problems - Page 106: 65
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
