Answer
Please see the work below.
Work Step by Step
We know that
$W=(\frac{1}{2})kx^2$
Now we can find the required ratio as
$\frac{k_B}{k_A}=(\frac{W_B}{W_A})(\frac{x_A}{x_B})^2=(\frac{2}{1})(\frac{2}{1})^2=8$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 6 - Exercises and Problems - Page 106: 53
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