Answer
Please see the work below.
Work Step by Step
We know that
$5g=\frac{v^2}{R}$
This can be rearranged as:
$R=\frac{v^2}{5g}$
We plug in the known values to obtain:
$R=\frac{(\frac{1200}{3.6})^2}{5(9.8)}$
$R=2300m$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 3 - Exercises and Problems - Page 49: 75
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