Answer
Please see the work below.
Work Step by Step
We know that
$a_r=\frac{v^2}{r}$
$r=\frac{v^2}{a_r}$
but $a_r=g$
Hence $r=\frac{v^2}{g}$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 3 - Exercises and Problems - Page 49: 74
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