Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 19 - Exercises and Problems - Page 350: 50

Answer

Please see the work below.

Work Step by Step

We know that $E_{unavailable}=nRTln\frac{V_2}{V_1}$ We plug in the known values to obtain: $E_{unavailable}=6.36\times 8.314\times 306$ $E_{unavailable}=43.6KJ$
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