Answer
140 MJ/K
Work Step by Step
We use the equation for the change in entropy:
$\Delta S =\frac{ m\times L_f}{T}+mcln(\frac{T_f}{T_0})$
$\Delta S =\frac{(94\times10^3)\times 334,000}{273}+(94,000)(4,184)ln(\frac{288}{273})=140\ MJ/K $
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