Answer
The proof is below.
Work Step by Step
We use the power that the exponential is raised to in order to find:
$1 = |\frac{-mv^2}{2kT}|$
$1 = |\frac{mv^2}{2kT}|$
$v = \sqrt{\frac{2kT}{m}}$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 17 - Exercises and Problems - Page 315: 76
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