Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 16 - Exercises and Problems - Page 301: 70

Answer

464,229 Watts

Work Step by Step

a) We use the equation for the rate of heat conduction, which is equation 16.5 in the book, to obtain: $H = -\frac{(80.4)(4.6)(3)}{.004}=277,380 \ Watts$ b) We use equation 16.9 in the textbook to find the rate of heat radiation: $P = (1)(5.67\times10^{-8})(4.6)(920)^4=186,849 \ Watts$ c) Thus, the total loss is: $\fbox{464,229 Watts}$
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