Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 14 - Exercises and Problems - Page 263: 66

Answer

$.0022\ kg$

Work Step by Step

We rearrange the equation for the frequency of a string/rope to find mass: $m= \frac{T}{4Lf^2}=\frac{667}{4(.389)(440^2)}=.0022\ kg$
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