Answer
a) 1.75
b) 29.78
c) .0134
d) 2209
e) 53
Work Step by Step
a) From the wave function, we see that the amplitude is 1.75.
b) We see that k is equal to .211. Thus, it follows that the wavelength is:
$\lambda = \frac{2\pi}{k}=\frac{2\pi}{.211}=29.78$
c) We see that $466 \ rads/s$ is the wave speed. Thus, it follows:
$T=\frac{2\pi}{\omega}=\frac{2\pi}{466}=.0134\ s$
d) We find:
$v = f\lambda = \frac{\lambda}{T} = \frac{29.78}{.0134} =2208.5 \ cm/s$
e) We find:
$P = \frac{1}{2}\mu v \omega^2 A^2$
This becomes:
$P = \frac{2\pi^2 A^2 F }{vT^2}$
Plugging in the known values gives:
$53 \ Watts$
