Answer
(a)$K=6.7\times 10^{-5}\frac{N}{m}$
(b)$m=3.4\times 10^{-10}Kg$
Work Step by Step
(a)We know that
$K=\frac{F}{x}$
We plug in the known values to obtain:
$K=\frac{1\times 10^{-12}}{15\times 10^{-9}}=6.7\times 10^{-5}\frac{N}{m}$
(b) We can find the mass as follows:
$m=\frac{K}{\omega^2}$
$\implies m=\frac{6.667\times 10^{-5}}{2\pi(70)^2}$
$m=3.4\times 10^{-10}Kg$
