Answer
1680 N/m
Work Step by Step
Using the equation that equates omega to the spring constant and the mass and using the equation $\omega= 2\pi f$, we find:
$k = 4\pi^2f^2m=4\pi^2(4\times10^{13})^2(2.66\times10^{-26})=\fbox{1680 N/m}$
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