Answer
a) 10 Hz
b) 62.8 rads/s
Work Step by Step
We find:
a) $ f= \frac{\omega}{t}=\frac{600}{60}=\fbox{10 Hz}$
b) We use the equation for omega:
$\omega = 2\pi f = 2\pi (10) = \fbox{62.8 rads/s}$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 13 - Exercises and Problems - Page 238: 32
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