Answer
a) 2.2 radians per second
b) 2.8 seconds
c) .63 meters
Work Step by Step
We find:
a) $\omega = \frac{a_{max}}{v_{max}}=\frac{3.1}{1.4}=\fbox{2.2 seconds}$
b) $ T = \frac{2\pi }{\omega} = \frac{2\pi }{2.2}= \fbox {2.8 seconds}$
c) We simplify the equation for the maximum possible speed to find:
$A = \frac{v_{max}}{\omega}= \frac{1.4}{2.2}=\fbox{.63 meters}$
