Answer
$54cm$
Work Step by Step
We know that
$F_x<2100N$
$\implies \frac{Mg\times 1.15}{1.4-d}<2100N$
$1.4-d>\frac{160\times 9.8\times 1.15}{2100}$
$1.4-d<0.86$
$d<1.4-0.86$
$d<54cm$
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