Answer
22,856 Newtons
Work Step by Step
We know that the net torque is 0, so it follows:
$(15)(2500)(9.81)sin40^{\circ}+5(830)(9.81)sin40^{\circ}=15F_tsin50^{\circ}$
$F_t = \fbox{22,856 Newtons }$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 12 - Exercises and Problems - Page 217: 36
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