Answer
1.4W
Work Step by Step
We know that all of the forces add up to zero. Thus, we find:
$w = T_1cos35^{\circ} +T_2 cos 60^{\circ}-W $
We can also find that the value of the first tension force is:
$T_2 = \frac{Wsin99.2}{.710}$
$T_1=\frac{sin60}{sin30}(\frac{Wsin 99.2}{.710})$ :
Plugging these values into the first equation, we find
$w=1.4W$
