Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 12 - Exercises and Problems - Page 216: 30

Answer

$T=71.2KN$

Work Step by Step

In the given scenario $\sum T_p=0$ $\implies mg\times 9cos50+Mg\times 18cos50-T\times 9sin40=0$ We plug in the known values to obtain: $T=\frac{1700\times 9.8\times 9cos50+2200\times 9.8\times 18cos50}{9sin40}$ This simplifies to: $T=71.2KN$
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