Answer
$6.67 \times 10^{-11} N$
Work Step by Step
$$F= G \frac{m_{1} m_{2}}{d^{2}} = $$
$$(6.67 \times 10^{-11} \frac {N \cdot m^{2}}{kg^{2}}) \frac{(1 kg)(1 kg)}{(1 m)^{2}} = $$
$$6.67 \times 10^{-11} N $$
This is discussed on page 163.
Conceptual Physics (12th Edition)
by Hewitt, Paul G.
Published by
Addison-Wesley
ISBN 10:
0321909100
ISBN 13:
978-0-32190-910-7
Chapter 9 - Reading Check Questions (Comprehension) - Page 177: 5
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