College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 7 - Circular Motion and Gravitation - Learning Path Questions and Exercises - Exercises - Page 261: 34

Answer

a). The string cannot be exactly horizontal because of the weight of the ball acting downwards. b). $7.845m/s$ c). $10.25N$

Work Step by Step

a). The string cannot be exactly horizontal because of the weight of the ball acting downwards. b). m=0.25kg, r=1.5m, t=1.2s for 1 revolution. $\omega=\frac{2pi}{1.2}=5.23rad/s$ $v=r\omega=1.5\times5.23=7.845m/s$ c). $F=ma_{c}=m\frac{v^{2}}{r}=10.25N$
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