Answer
Ratio of final to initial potential energy $=0.04$
Work Step by Step
Ratio of final to initial potential energy =
$\frac{PE_{f}}{PE_{i}}=\frac{kx_{f}^{2}}{kx_{i}^{2}}=\frac{3^{2}}{15^{2}}=0.04$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 5 - Work and Energy - Learning Path Questions and Exercises - Exercises - Page 176: 42
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